WGU Applied-Algebra Exam Dumps

The graph is a logistic growth curve.

A logistic growth curve has two main concavity regions:

and

From the graph, the function increases faster and faster until about:

After , the graph continues increasing, but it begins to flatten out. That means the number of members is increasing slower and slower.

This is concave down behavior.

Therefore, one interval where the graph is concave down is:

So the correct answer is:

The graph models the number of widgets the team can produce each day.

The horizontal axis represents:

The vertical axis represents:

The graph gives two labeled points:

and

The average rate of change is:

Substitute the values:

Rounded to the nearest tenth:

This means the team increased production by an average of approximately:

Therefore, the correct answer is:

The value measures how well a regression model fits the data.

Here:

This is a low value, meaning the model explains only about:

of the variation in the data.

That indicates a weak fit. When a model has a weak fit, using it for extrapolation is not reliable because predictions outside the data range may be very inaccurate.

Since:

the best conclusion is that extrapolation is not appropriate because the regression model does not fit the data well enough.

Therefore, the correct answer is:

The graph shows an increasing exponential curve.

The number of subscribers is going up as time passes, so the function is increasing.

Also, the graph becomes steeper as time increases. This means the rate of increase is getting larger.

So the number of subscribers is:

This is a key feature of exponential growth.

Because the vehicle is traveling away from the town at a fixed rate, the distance can be modeled by a linear function:

where:

and

We are given two points:

and

These mean:

After hour, the vehicle is miles away.

After hours, the vehicle is miles away.

First, find the rate of change:

So the vehicle is moving away from the town at a rate of:

Now the function has the form:

Use the point to find :

Therefore, the function is:

Check using :