Salesforce JS-Dev-101 Exam Dumps

Get All Salesforce Certified JavaScript Developer Exam Questions with Validated Answers

JS-Dev-101 Pack
Vendor: Salesforce
Exam Code: JS-Dev-101
Exam Name: Salesforce Certified JavaScript Developer
Exam Questions: 147
Last Updated: August 20, 2026
Related Certifications: Salesforce Developer
Exam Tags: Professional Salesforce DevelopersJavaScript ProgrammerFront End Developer
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Free Salesforce JS-Dev-101 Exam Actual Questions

Question No. 1

Given the following code:

01 counter = 0;

02 const logCounter = () => {

03 console.log(counter);

04 };

05 logCounter();

06 setTimeout(logCounter, 2100);

07 setInterval(() => {

08 counter++;

09 logCounter();

10 }, 1000);

What will be the first four numbers logged?

Show Answer Hide Answer
Correct Answer: A

We need to track the value of counter and the timing of each call to logCounter.

Initial state:

Line 01: counter = 0;

Line 02--04: logCounter logs the current value of counter.

Execution order and timing:

Line 05: logCounter();

Called immediately at time t = 0 ms.

counter is 0.

First log: 0.

Line 06: setTimeout(logCounter, 2100);

Schedules logCounter to run once after 2100 ms.

No log yet at this line.

Line 07--10: setInterval(() => { counter++; logCounter(); }, 1000);

Schedules a repeating callback every 1000 ms (1 second).

First interval callback runs at t 1000 ms.

Now follow the timeline:

t = 0 ms:

logCounter(); from line 05

Logs: 0

t = 1000 ms (first interval execution):

counter++; counter goes from 0 to 1.

logCounter(); logs 1.

t = 2000 ms (second interval execution):

counter++; counter goes from 1 to 2.

logCounter(); logs 2.

t = 2100 ms (timeout from line 06):

logCounter(); runs again.

counter is still 2 (next setInterval will be at t = 3000 ms).

Logs 2.

So the first four logs are:

0

1

2

2

Concatenated as in the options: 0122.

Therefore, the correct choice is:

Answe r: A

Study Guide / Concept Reference (no links):

setTimeout and setInterval timing behavior

Order of execution in the event loop

Closures capturing variables (here, logCounter using counter)

Understanding asynchronous scheduling in JavaScript


Question No. 2

Refer to the code:

01 function execute() {

02 return new Promise((resolve, reject) => reject());

03 }

04 let promise = execute();

05

06 promise

07 .then(() => console.log('Resolved1'))

08 .then(() => console.log('Resolved2'))

09 .then(() => console.log('Resolved3'))

10 .catch(() => console.log('Rejected'))

11 .then(() => console.log('Resolved4'));

What is the result when the Promise in the execute function is rejected?

Show Answer Hide Answer
Correct Answer: D

execute() returns a Promise that immediately calls reject().

So promise starts in a rejected state.

When a Promise is rejected and you chain .then() calls without rejection handlers, all those .then() callbacks are skipped until a .catch() is encountered:

promise

.then(...) // skipped

.then(...) // skipped

.then(...) // skipped

.catch(...) // executed

.then(...); // executed after catch

Execution:

.then(() => console.log('Resolved1')) is skipped.

.then(() => console.log('Resolved2')) is skipped.

.then(() => console.log('Resolved3')) is skipped.

.catch(() => console.log('Rejected')) runs and logs Rejected.

The .catch() returns a resolved Promise (no explicit return, so undefined), so the next .then() runs:

.then(() => console.log('Resolved4')) logs Resolved4.

Final output:

Rejected

Resolved4

This matches option D.


Question No. 3

A Node.js server library uses events and callbacks. The developer wants to log any issues the server has at boot time.

Which code logs an error with an event?

Show Answer Hide Answer
Correct Answer: C

Node.js event-based modules use the EventEmitter pattern.

The correct syntax for listening to events is:

emitter.on('eventName', callback)

The server library emits an 'error' event, which must be listened to using .on.

Option analysis:

A: .catch is for Promises, not EventEmitters.

B: .error is not an EventEmitter method.

C: Correct. Listens to the 'error' event.

D: try...catch only captures synchronous errors, not event-based asynchronous errors.

Therefore, the correct answer is option C.

JavaScript Knowledge Reference (text-only)

The EventEmitter API uses on(event, handler) to listen for events.

Errors emitted asynchronously cannot be caught with try...catch.

The 'error' event is standard for Node.js modules to signal operational errors.


Question No. 4

A developer wants to create a simple image upload using the File API.

HTML:

Image preview...

JavaScript:

01 function previewFile() {

02 const preview = document.querySelector('img');

03 const file = document.querySelector('input[type=file]').files[0];

04 // line 4 code

05 reader.addEventListener("load", () => {

06 preview.src = reader.result;

07 }, false);

08 // line 8 code

09 }

Which code in lines 04 and 08 allows the selected local image to be displayed?

Show Answer Hide Answer
Correct Answer: B

The File API in browsers provides the FileReader object to read file contents selected from <input type='file'>.

Important knowledge points:

new FileReader() creates a file-reading object.

.readAsDataURL(file) reads a file and produces a Base64 URL string.

The 'load' event fires when the file has finished reading.

reader.result contains the data URL after reading completes.

Therefore, the correct implementation must:

Create a FileReader instance:

const reader = new FileReader();

Call:

reader.readAsDataURL(file);

Use the load event handler to assign the image preview:

preview.src = reader.result;

Option B is the only option that matches valid JavaScript File API usage.

Option A is incorrect because File is not a constructor for reading files.

Option C is incorrect because URL.createObjectURL(file) must be assigned directly as a URL, not used with reader.result.

JavaScript Knowledge Reference (text-only)

The file-reading interface in browsers is FileReader.

readAsDataURL() loads files as Base64 data URLs.

The load event indicates when the reader has finished and reader.result is available.

==================================================


Question No. 5

A developer publishes a new version of a package with new features that do not break backward compatibility. The previous version number was 1.1.3.

Following semantic versioning formats, what should the new package version number be?

Show Answer Hide Answer
Correct Answer: D

The correct answer is D.

Semantic versioning usually follows this format:

MAJOR.MINOR.PATCH

For the version:

1.1.3

The parts are:

1 = MAJOR

1 = MINOR

3 = PATCH

A package version should be updated based on the type of change:

MAJOR version changes when there are breaking changes.

MINOR version changes when new features are added in a backward-compatible way.

PATCH version changes when backward-compatible bug fixes are added.

The question says the developer added new features that do not break backward compatibility. That means the minor version should increase.

Starting version:

1.1.3

Increase the minor version from 1 to 2, and reset the patch version to 0:

1.2.0

Why the other options are incorrect:

A . 1.2.3 is incorrect because when the minor version increases, the patch version should reset to 0.

B . 1.1.4 is incorrect because that would represent a patch update, usually for bug fixes, not new features.

C . 2.0.0 is incorrect because that would represent a major version update, usually for breaking changes.

D . 1.2.0 is correct because it represents a backward-compatible feature release.

Therefore, the verified answe r is D.


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