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Get All Databricks Certified Associate Developer for Apache Spark 3.0 Exam Questions with Validated Answers
| Vendor: | Databricks |
|---|---|
| Exam Code: | Databricks-Certified-Associate-Developer-for-Apache-Spark-3.0 |
| Exam Name: | Databricks Certified Associate Developer for Apache Spark 3.0 |
| Exam Questions: | 180 |
| Last Updated: | October 6, 2026 |
| Related Certifications: | Apache Spark Associate Developer |
| Exam Tags: |
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Which of the following code blocks reads in parquet file /FileStore/imports.parquet as a DataFrame?
Which of the following describes Spark's standalone deployment mode?
Standalone mode uses only a single executor per worker per application.
This is correct and a limitation of Spark's standalone mode.
Standalone mode is a viable solution for clusters that run multiple frameworks.
Incorrect. A limitation of standalone mode is that Apache Spark must be the only framework running on the cluster. If you would want to run multiple frameworks on the same cluster in parallel, for
example Apache Spark and Apache Flink, you would consider the YARN deployment mode.
Standalone mode uses a single JVM to run Spark driver and executor processes.
No, this is what local mode does.
Standalone mode is how Spark runs on YARN and Mesos clusters.
No. YARN and Mesos modes are two deployment modes that are different from standalone mode. These modes allow Spark to run alongside other frameworks on a cluster. When Spark is run in
standalone mode, only the Spark framework can run on the cluster.
Standalone mode means that the cluster does not contain the driver.
Incorrect, the cluster does not contain the driver in client mode, but in standalone mode the driver runs on a node in the cluster.
More info: Learning Spark, 2nd Edition, Chapter 1
Which of the following code blocks reads in the two-partition parquet file stored at filePath, making sure all columns are included exactly once even though each partition has a different schema?
Schema of first partition:
1. root
2. |-- transactionId: integer (nullable = true)
3. |-- predError: integer (nullable = true)
4. |-- value: integer (nullable = true)
5. |-- storeId: integer (nullable = true)
6. |-- productId: integer (nullable = true)
7. |-- f: integer (nullable = true)
Schema of second partition:
1. root
2. |-- transactionId: integer (nullable = true)
3. |-- predError: integer (nullable = true)
4. |-- value: integer (nullable = true)
5. |-- storeId: integer (nullable = true)
6. |-- rollId: integer (nullable = true)
7. |-- f: integer (nullable = true)
8. |-- tax_id: integer (nullable = false)
This is a very tricky Question: and involves both knowledge about merging as well as schemas when reading parquet files.
spark.read.option('mergeSchema', 'true').parquet(filePath)
Correct. Spark's DataFrameReader's mergeSchema option will work well here, since columns that appear in both partitions have matching data types. Note that mergeSchema would fail if one or
more columns with the same name that appear in both partitions would have different data types.
spark.read.parquet(filePath)
Incorrect. While this would read in data from both partitions, only the schema in the parquet file that is read in first would be considered, so some columns that appear only in the second partition
(e.g. tax_id) would be lost.
nx = 0
for file in dbutils.fs.ls(filePath):
if not file.name.endswith('.parquet'):
continue
df_temp = spark.read.parquet(file.path)
if nx == 0:
df = df_temp
else:
df = df.union(df_temp)
nx = nx+1
df
Wrong. The key idea of this solution is the DataFrame.union() command. While this command merges all data, it requires that both partitions have the exact same number of columns with identical
data types.
spark.read.parquet(filePath, mergeSchema='y')
False. While using the mergeSchema option is the correct way to solve this problem and it can even be called with DataFrameReader.parquet() as in the code block, it accepts the value True as a
boolean or string variable. But 'y' is not a valid option.
nx = 0
for file in dbutils.fs.ls(filePath):
if not file.name.endswith('.parquet'):
continue
df_temp = spark.read.parquet(file.path)
if nx == 0:
df = df_temp
else:
df = df.join(df_temp, how='outer')
nx = nx+1
df
No. This provokes a full outer join. While the resulting DataFrame will have all columns of both partitions, columns that appear in both partitions will be duplicated - the Question: says all
columns that
are included in the partitions should appear exactly once.
More info: Merging different schemas in Apache Spark | by Thiago Cordon | Data Arena | Medium
Static notebook | Dynamic notebook: See test 3, Question: 37 (Databricks import instructions)
Which of the following code blocks returns a copy of DataFrame transactionsDf where the column storeId has been converted to string type?
This Question: asks for your knowledge about the cast syntax. cast is a method of the Column class. It is worth noting that one could also convert a column type using the Column.astype()
method, which is just an alias for cast.
Find more info in the documentation linked below.
More info: pyspark.sql.Column.cast --- PySpark 3.1.2 documentation
Static notebook | Dynamic notebook: See test 2, Question: 33 (Databricks import instructions)
Which of the following describes a difference between Spark's cluster and client execution modes?
In cluster mode, the driver resides on a worker node, while it resides on an edge node in client mode.
Correct. The idea of Spark's client mode is that workloads can be executed from an edge node, also known as gateway machine, from outside the cluster. The most common way to execute Spark
however is in cluster mode, where the driver resides on a worker node.
In practice, in client mode, there are tight constraints about the data transfer speed relative to the data transfer speed between worker nodes in the cluster. Also, any job in that is executed in client
mode will fail if the edge node fails. For these reasons, client mode is usually not used in a production environment.
In cluster mode, the cluster manager resides on a worker node, while it resides on an edge node in client execution mode.
No. In both execution modes, the cluster manager may reside on a worker node, but it does not reside on an edge node in client mode.
In cluster mode, executor processes run on worker nodes, while they run on gateway nodes in client mode.
This is incorrect. Only the driver runs on gateway nodes (also known as 'edge nodes') in client mode, but not the executor processes.
In cluster mode, the Spark driver is not co-located with the cluster manager, while it is co-located in client mode.
No, in client mode, the Spark driver is not co-located with the driver. The whole point of client mode is that the driver is outside the cluster and not associated with the resource that manages the
cluster (the machine that runs the cluster manager).
In cluster mode, a gateway machine hosts the driver, while it is co-located with the executor in client mode.
No, it is exactly the opposite: There are no gateway machines in cluster mode, but in client mode, they host the driver.
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